The correct order of the second ionization en | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The electronic configurations of the elements are:$C (Z=6): 1s^2 2s^2 2p^2$$N (Z=7): 1s^2 2s^2 2p^3$$O (Z=8): 1s^2 2s^2 2p^4$$F (Z=9): 1s^2 2s^2 2

Vedclass · Accepted Answer

$O > F > N > C$

Vedclass · Answer

(C) The electronic configurations of the elements are:$C (Z=6): 1s^2 2s^2 2p^2$$N (Z=7): 1s^2 2s^2 2p^3$$O (Z=8): 1s^2 2s^2 2p^4$$F (Z=9): 1s^2 2s^2 2p^5$For the second ionization energy,we remove one electron to form the $M^+$ ion:$C^+: 1s^2 2s^2 2p^1$$N^+: 1s^2 2s^2 2p^2$$O^+: 1s^2 2s^2 2p^3$ (Half-filled $p$-orbital,highly stable)$F^+: 1s^2 2s^2 2p^4$Due to the stable half-filled $2p^3$ configuration of $O^+$,it has the highest second ionization energy.Comparing the remaining,$F^+$ has a higher effective nuclear charge than $N^+$,and $N^+$ is higher than $C^+$.Therefore,the correct order is $O > F > N > C$.

The correct order of the second ionization energy of $C$,$N$,$O$,and $F$ is :-

Similar Questions

The value of ionization energy of noble gases is ......... .

What are the first ionization potentials $(eV)$ of $Be$ and $Ba$ respectively?

Among the second period elements,the actual ionization enthalpies are in the order $Li < B < Be < C < O < N < F < Ne$. Explain why:
$(i)$ $Be$ has higher $\Delta_{i}H$ than $B$
$(ii)$ $O$ has lower $\Delta_{i}H$ than $N$ and $F$?

If the first ionisation enthalpy of $Li$,$Be$,and $C$ respectively are $520$,$899$,and $1086 \ kJ \ mol^{-1}$,the first ionisation enthalpy (in $kJ \ mol^{-1}$) of $B$ will be:

Which statement is correct regarding ionisation potential?

Vedclass Test Series

Exam Paper Generator

Online Exam Module